For every continuous $f$ there is an absolutely continuous $g$ such that $[f=g]$ is not bilaterally strongly porous
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- by Z. Buczolich PDF
- Proc. Amer. Math. Soc. 100 (1987), 485-488 Request permission
Abstract:
For any Darboux function $f:\left [ {0,1} \right ] \to {\mathbf {R}}$ and any $0 < \delta < 1$ there is a point $x \in \left [ {0,1 - \delta } \right ]$ and a sequence ${x_n}$ such that (a) ${x_n} \in \left [ {x + {\delta ^{n + 1}},x + {\delta ^n}} \right ]\left ( {n = 1,2, \ldots } \right )$ and (b)$\sum \nolimits _{n = 2}^\infty {\left | {f\left ( {{x_n}} \right ) - f\left ( {{x_{n - 1}}} \right )} \right |} < + \infty$. Consequently, for every $f \in C\left [ {0,1} \right ]$ there is an absolutely continuous function $g$ such that $\left \{ {x:f\left ( x \right ) = g\left ( x \right )} \right \}$ is not bilaterally strongly porous.References
- P. Humke and M. Laczkovich, Typical continuous functions are virtually nonmonotone, Proc. Amer. Math. Soc. 94 (1985), no. 2, 244–248. MR 784172, DOI 10.1090/S0002-9939-1985-0784172-7
Additional Information
- © Copyright 1987 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 100 (1987), 485-488
- MSC: Primary 26A46; Secondary 26A15
- DOI: https://doi.org/10.1090/S0002-9939-1987-0891151-X
- MathSciNet review: 891151