The Diophantine equation $x^ 2=4q^ n+4q^ m+1$
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- by Mao Hua Le PDF
- Proc. Amer. Math. Soc. 106 (1989), 599-604 Request permission
Abstract:
Let $q = {p^r}$ be a prime power. In this paper, we prove that the equation ${x^2} = 4{q^n} + 4{q^m} + 1,m < n,{\text {g}}{\text {.c}}{\text {.d}}{\text {.}}(m,n) = 1$ has no positive integer solution $(m,n,x)$ with $m > 2$.References
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Additional Information
- © Copyright 1989 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 106 (1989), 599-604
- MSC: Primary 11D61
- DOI: https://doi.org/10.1090/S0002-9939-1989-0968624-6
- MathSciNet review: 968624