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Picard's theorem and Rickman's theorem by way of Harnack's inequality

Author: John L. Lewis
Journal: Proc. Amer. Math. Soc. 122 (1994), 199-206
MSC: Primary 30C65
MathSciNet review: 1195483
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Abstract: In this note we give a very elementary proof of Picard's Theorem and Rickman's Theorem which uses only Harnack's inequality.

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Keywords: Picard's theorem, harmonic functions, Harnack's inequality, quasiregular mappings, omitted values, unique continuation
Article copyright: © Copyright 1994 American Mathematical Society

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