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Transactions of the American Mathematical Society

Published by the American Mathematical Society since 1900, Transactions of the American Mathematical Society is devoted to longer research articles in all areas of pure and applied mathematics.

ISSN 1088-6850 (online) ISSN 0002-9947 (print)

The 2020 MCQ for Transactions of the American Mathematical Society is 1.48.

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$G_{2n}$ spaces
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by Donald O. Koehler PDF
Trans. Amer. Math. Soc. 150 (1970), 507-518 Request permission

Abstract:

A complex normed linear space $X$ will be called a ${G_{2n}}$ space if and only if there is a mapping $\left \langle { \cdot , \ldots , \cdot } \right \rangle$ from ${X^{2n}}$ into the complex numbers such that: ${x_k} \to \left \langle {{x_1}, \ldots ,{x_{2n}}} \right \rangle$ is linear for $k = 1, \ldots ,n;\left \langle {{x_1}, \ldots ,{x_{2n}}} \right \rangle = {\left \langle {{x_{2n}}, \ldots ,{x_1}} \right \rangle ^ - }$; and ${\left \langle {x, \ldots ,x} \right \rangle ^{1/2n}} = ||x||$. The basic models are the ${L^{2n}}$ spaces, but one also has that every inner product space is a ${G_{2n}}$ space for every integer $n$. Hence ${G_{2n}}$ spaces of a given cardinality need not be isometrically isomorphic. It is shown that a complex normed linear space is a ${G_{2n}}$ space if and only if the norm satisfies a generalized parallelogram law. From the proof of this characterization it follows that a linear map $U$ from $X$ to $X$ is an isometry if and only if $\left \langle {U({x_1}), \ldots ,U({x_{2n}})} \right \rangle = \left \langle {{x_1}, \ldots ,{x_{2n}}} \right \rangle$ for all ${x_1}, \ldots ,{x_{2n}}$. This then provides a way to construct all of the isometries of a finite dimensional ${G_{2n}}$ space. Of particular interest are the $\operatorname {CBS} {G_{2n}}$ spaces in which $|\left \langle {{x_1}, \ldots ,{x_{2n}}} \right \rangle | \leqq ||{x_1}|| \cdots ||{x_{2n}}||$. These spaces have many properties similar to inner product spaces. An operator $A$ on a complete $\operatorname {CBS} {G_{2n}}$ space is said to be symmetric if and only if $\left \langle {{x_1}, \ldots ,A({x_i}), \ldots ,{x_{2n}}} \right \rangle = \left \langle {{x_1}, \ldots ,A({x_j}), \ldots ,{x_{2n}}} \right \rangle$ for all $i$ and $j$. It is easy to show that these operators are scalar and that on ${L^{2n}},n > 1$, they characterize multiplication by a real ${L^\infty }$ function. The interest in nontrivial symmetric operators is that they exist if and only if the space can be decomposed into the direct sum of nontrivial ${G_{2n}}$ spaces.
References
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Additional Information
  • © Copyright 1970 American Mathematical Society
  • Journal: Trans. Amer. Math. Soc. 150 (1970), 507-518
  • MSC: Primary 46.15; Secondary 47.00
  • DOI: https://doi.org/10.1090/S0002-9947-1970-0262806-7
  • MathSciNet review: 0262806