Positive solutions for 2nth-order singular sub-linear m-point boundary value problems

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Abstract

This paper investigates the existence of positive solutions for 2nth-order singular sub-linear m-point boundary value problems. Firstly, we establish a comparison theorem, then we define a partial ordering in C2n−2 [a, b]  C2n(a, b) and construct lower and upper solutions to give a necessary and sufficient condition for the existence of C2n−2[0, 1] as well as C2n−1[0, 1] positive solutions. Our nonlinearity f(t, x1, x2,  , xn) may be singular at xi = 0, i = 1, 2,  , n, t = 0 and/or t = 1.

Introduction

The singular ordinary differential equations arise in the fields of gas dynamics, Newtonian fluid mechanics, the theory of boundary layer and so on. The theory of singular boundary value problems has become an important area of investigation in recent years (see [1], [2], [3], [4], [5], [6] and the references therein).

The existence of solutions of multi-point boundary value problems has been studied by many authors using nonlinear alternative of Leray–Schauder, Coincidence degree theory and fixed point theorem in cones (see [7], [8], [9], [10], [11] and references therein).

Very recently, the existence of positive solutions and multiple positive solutions of singular second order multi-point boundary value problem have been studied by papers [12], [13], [14] using the fixed point index and approximate process; Zhang and Wang in [15] gave some sufficient conditions for the existence results of a class of singular nonlinear second order three-point boundary value problems by the upper and lower solution method and the monotone iterative technique. But they only considered the case: nonlinear function f(t, x) cannot be singular at x = 0.

On the boundary value problems of 2nth-order ordinary differential equation(-1)nx(2n)(t)=f(t,x(t),-x(t),,(-1)ix(2i)(t),,(-1)n-1x(2n-2)(t)),t(0,1),x(2i)(0)=x(2i)(1)=0,i=0,1,2,,n-1.

For the special case n = 2, function f  C([0, 1] × R × R, R) in (*), i.e. f is continuous, problem (*) is nonsingular, the existence and uniqueness of positive solutions of (*) have been studied by papers [16], [17], [18], [19].

A sufficient condition for the existence of solutions of the singular problem (*) was given by O’Regan in [20] with a topological transversal theorem.

For the general case n  2: the function f  C([0, 1] × Rn, R) in (*), i.e. f is continuous, problem (*) is nonsingular, the existence of one or more solutions of (*) a have been studied by papers [21], [22], [23]. The function fC((0,1)×R+n,R+) in (1.1), i.e. f is singular at t = 0 or t = 1, but f is continuous at xi, i = 1, 2,  , n, paper [24] has investigated super-linear singular boundary value problem (*) and obtained some necessary and sufficient conditions for the existence of C2n−2[0, 1] as well as C2n−1[0, 1] positive solutions by means of the fixed point theorems on cones.

In this paper, we shall consider the existence of positive solutions for 2nth-order singular m-point boundary value problems of the following differential equation:(-1)nx(2n)(t)=f(t,x(t),-x(t),,(-1)ix(2i)(t),,(-1)n-1x(2n-2)(t)),t(0,1),x(2i)(0)=0,x(2i)(1)=j=1m-2kijx(2i)(ηj),i=0,1,2,,n-1,where 0 < kij < 1, j = 1, 2,  , m  2, j=1m-2kij<1,i=1,2,,n-1, 0 < η1 < η2 <  < ηm−2 < 1, are constants, m  3 and n > 1 is an integer, and f satisfies the following hypothesis.

(H): f  C((0, 1) × (0, ∞)n, [0, ∞)), and there exist constants λi, μi, (−∞ < λi  0  μi, i = 1, 2,  , n, μn < 1, i=1nμi<1) such that for t  (0, 1), xi  (0, ∞)cμif(t,x1,x2,,xi,,xn)f(t,x1,x2,,cxi,,xn)cλif(t,x1,x2,,xi,,xn)if0<c1,i=1,2,,n.

Remark 1

Inequality (1.3) impliescλif(t,x1,x2,,xi,,xn)f(t,x1,x2,,cxi,,xn)cμif(t,x1,x2,,xi,,xn)ifc1,i=1,2,,n.

Typical functions that satisfy the above sub-linear hypothesis are those taking the form f(t,x1,x2,,xn)=i=1mpi(t)x1i1x2i2xnin; here pj(t)  C(0, 1), pj(t) > 0 on (0, 1), ℓjk  R, ℓjn < 1, j = 1, 2,  , m, k = 1, 2,  , n, i=1mk=1nmax{0,ik}<1.

By singularity we mean that the function f(t, x1, x2,  , xi,  , xn) in (1.1) is allowed to be unbounded at xi, i = 1, 2,  , n, t = 0 and/or t = 1. A function x(t)  C2n−2 [0, 1]  C2n(0, 1) is called a C2n−2[0, 1] (positive) solution of (1.1), (1.2) if it satisfies (1.1), (1.2) ((−1)ix(2i)(t) > 0, i = 0, 1, 2,  , n  1 for t  (0, 1)). A C2n−2[0, 1] (positive) solution of (1.1), (1.2) is called a C2n−1[0, 1] (positive) solution if x(2n−1)(0+) and x(2n−1)(1) both exist ((−1)ix(2i)(t) > 0, i = 0, 1, 2,  , n  1 for t  (0, 1)).

For the general case n  2: the function f  C([0, 1] × Rn, R) in (1.1), i.e. f is continuous, problem (1.1), (1.2) is nonsingular, the existence of one or more solutions of (1.1), (1.2) have been studied by papers [25], [26] with the fixed point theorem.

In this paper, we shall study the existence of positive solutions for 2nth-order singular sub-linear m-point boundary value problem (1.1), (1.2). Firstly, we establish a comparison theorem, then we define a partial ordering in C2n−2[a, b]  C2n(a, b) and construct lower and upper solutions to give a necessary and sufficient condition for the existence of C2n−2 [0, 1] as well as C2n−1[0, 1] positive solutions. Our nonlinearity f(t, x1, x2,  , xn) may be singular at xi = 0, i = 1, 2,  , n, t = 0 and/or t = 1.

Section snippets

Several lemmas

To prove the main result, we need the following lemmas.

Suppose that 0  a < η1 < ηm−2 < b, andF=xC2n-2[a,b]C2n(a,b),(-1)ix(2i)(a)0,(-1)ix(2i)(b)-j=1m-2kijx(2i)(ηj)0,i=0,1,2,,n-1.

Lemma 2.1 A comparison theorem

If x  F such that (1)nx(2n)(t)  0, t  (a, b), then(-1)ix(2i)(t)0,t[a,b],i=0,1,2,,n-1.

Proof

Set(-1)ix(2i)(a)=xa(i),(-1)ix(2i)(b)-j=1m-2kijx(2i)(ηj)=xb(i),i=0,1,2,,n-1thenxa(i)0,xb(i)0,i=0,1,2,,n-1,(-1)ix(2i)(t)=y1(t)y1(a)xa(i)+t-a(b-a)-j=1m-2kij(ηj-a)xb(i)+abG(t,s)[(-1)i+1x(2i+2)(s)]ds+t-a(b-a)-j=1m-2kij(ηj-a)j=1m-2kija

The main results

For convenience, we setF1(t)=f(t,t,t,,t,1),F2(t)=f(t,t,t,,t,t).

The main results of this paper are the following two theorems.

Theorem 3.1

Suppose (H) holds, then a necessary and sufficient condition for problem (1.1) and (1.2) to have C2n2[0, 1] positive solutions is that the following integral conditions hold:0<01t(1-t)F1(t)dt<,limt0+tt1(1-s)F1(s)ds=0,limt1-(1-t)0tsF1(s)ds=0.

Theorem 3.2

Suppose (H) holds, then a necessary and sufficient condition for problem (1.1) and (1.2) to have C2n1[0, 1] positive

Remark and examples

Remark 2

Consider the singular m-point boundary value problem (1.1) andx(2i)(0)=j=1m-2kijx(2i)(ηj),x(2i)(1)=0,i=0,1,2,,n-1.

Firstly, we define the linear operators B0, B1,  , Bn−1 as follows:Bix(t)=01H(t,s)x(s)ds+1-t1-j=1m-2kij(1-ηj)j=1m-2kij01H(ηi,s)x(s)ds,i=0,1,2,,n-1,where H(t, s) is given by (2.9).

For convenience, we setF3(t)=f(t,(1-t),(1-t),,(1-t),1),F4(t)=f(t,(1-t),(1-t),,(1-t),(1-t)).

By analogous methods, we have the following results.

Assume that x(t) is a C2n−1[0, 1] positive solution of

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Research supported by the NNSF-China (10471077), the NSF of Shandong Province (Y2004A01) and the XNF of SDJZU (XN040101).

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