Landau’s theorem for certain biharmonic mappings☆
Introduction
A four times continuously differentiable complex-valued function in a domain is biharmonic if and only if the Laplacian of F is harmonic. Note that is harmonic in D if F satisfies the biharmonic equation , where represents the Laplacian operator
Biharmonic functions arise in a lot of physical situations, particularly in fluid dynamics and elasticity problems, and have many important applications in engineering and biology (see [10], [12], [13] for the details).
It has been shown that a mapping F is biharmonic in a simply connected domain D if and only if F has the following representation:where G and K are complex-valued harmonic functions in D (see [2], [3]). Also, it is known that (see [5], [7]) G and K can be expressed aswhere , , and are analytic in D. The Jacobian of f is defined by
We now introduce
Then if .
In [3], the authors considered the following differential operator L defined on the class of complex-valued functions:
Clearly, L is a complex linear operator and satisfies the usual product rule:where are complex constants, f and g are functions. In addition, the operator L possesses a number of interesting properties. For instance. it is easy to see that the operator L preserves both harmonicity and biharmonicity. Many other basic properties are stated in [3].
Throughout the paper, we use the notation , , and we now recall one of the main results from [3]. Theorem A [3, Corollary 1(3)] Let F be a univalent biharmonic function in . If F is convex and is univalent, then is starlike.
At this place, it is also important to recall that (see [3, Corollary 1(3)]) the operator for biharmonic functions behaves much like for analytic functions, for example in the sense that for F univalent and biharmonic, F is starlike if and only if . A similar characterization has also been obtained by the authors for convex (biharmonic) functions.
The classical theorem of Landau shows that there exists a such that every function f, analytic in the unit disk with and in , is univalent in the disk and in addition, the range contains a disk of radius . Recently, many authors considered Landau’s theorem for planar harmonic mappings (see, for example, [4], [6], [8], [14]) and biharmonic mappings (see [1]). From Theorem A, we see that it is significant to consider Landau’s theorem for biharmonic mappings of the form , where F belongs to the class of biharmonic mappings. The main aim of this paper is to consider this problem. Our main results are the following. Theorem 1.1 Let be a biharmonic mapping in such that , , where G and K are harmonic in . Assume that both and are bounded by M. Then there is a constant such that is univalent in , where satisfies the following equation:where is the minimum value of the functionfor . The minimum is attained at . Moreover, the range contains a schlicht disk , where
It is important to remark that the bounds of G and K are not preserved under the differential operator L. In our next result we deal with the case . Then the result differs from Theorem 1.1, because for , the Jacobian . Therefore, we need to assume that instead. Theorem 1.2 Let be a biharmonic mapping in such that , and , where G is harmonic in . Then there is a constant such that is univalent in , where satisfies the following equation:where is defined as in Theorem 1.1. Moreover, contains a schlicht disk with
Denote the values in Theorem 1.1, Theorem 1.2 by and , respectively. In the left half of Table 1, we indicate the precise values of these ’s and the corresponding values of ’s for various choices of M. These values are obtained using Mathematica. Remark 1.3 Theorem 1.1, Theorem 1.2 are not sharp.
Also, it could be of some interest to see some numerical examples to compare the situation for biharmonic F obtained in [1] and for obtained in the present article. Thus, for a computational comparison with the recent results from [1], we recall their results in Theorem B, Theorem C to present the corresponding numerical values in Table 1, Table 2. The numerical values given in these two tables are self-explanatory. Theorem B Let be a biharmonic mapping of the unit disk , where G and K are harmonic in such that , , and both and are bounded by M. Then there is a constant so that F is univalent for . In specific satisfiesand contains a schlicht disk , whereThis result is not sharp. Theorem C Let G be harmonic in such that , and . Then there is a constant so that is univalent in the disk . is the solution of the equationand contains a disk withThe result is not sharp.
In Section 2, some elementary results will be recalled. The proofs of the main theorems will be presented in Sections 3 Proof for the case, 4 Proof for the case.
Section snippets
Some lemmas
In [4], [14], the following version of Schwarz lemma was obtained. Lemma D Let f be a harmonic mapping of the unit disk such that and . Thenand
The inequality (2.1) is due to Heinz [11, Lemma]. By Lemma D and the Heinz Lemma, the following is obvious. Corollary E Let f be a harmonic mapping of the unit disk such that and . Thenfor some absolute constant .
In [9], Hall proved that the sharp value c in
Proof for the case
We begin with the following three preliminary results. As an immediate consequence of Lemma F, we have Corollary 3.1 Let f be a harmonic function in which is n times continuously differentiable and . If , and , then for any ,
The conclusion of the following lemmas are obvious. Lemma 3.2 Let M and q be positive real constants. Then the functionis continuous and
Proof of Theorem 1.2
Assume that G is harmonic in . Then, we may set , whereand By the hypothesis on G and Lemma D, we obtain that
Now, we let . Thenand
Fix with , where m is the same as that in the proof of Theorem 1.1. Choose two distinct points and in the disk , and .
As before, we use Lemma D
Acknowledgement
The authors would like to thank the referee for the careful reading of this paper and the useful suggestions.
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The research was partly supported by NSFs of China (No. 10771059) and of Hunan Province (No. 05JJ10001), and NCET (No. 04-0783).