On a symplectic generalization of Petrie’s conjecture
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Abstract:
Motivated by the Petrie conjecture, we consider the following questions: Let a circle act in a Hamiltonian fashion on a compact symplectic manifold $(M,\omega )$ which satisfies $H^{2i}(M;\mathbb {R}) = H^{2i}({\mathbb C}{\mathbb P}^n,\mathbb {R})$ for all $i$. Is $H^j(M;\mathbb {Z}) = H^j({\mathbb C}{\mathbb P}^n;\mathbb {Z})$ for all $j$? Is the total Chern class of $M$ determined by the cohomology ring $H^*(M;\mathbb {Z})$? We answer these questions in the six-dimensional case by showing that $H^j(M;\mathbb {Z})$ is equal to $H^j({\mathbb C}{\mathbb P}^3;\mathbb {Z})$ for all $j$, by proving that only four cohomology rings can arise, and by computing the total Chern class in each case. We also prove that there are no exotic actions. More precisely, if $H^*(M;\mathbb {Z})$ is isomorphic to $H^*({\mathbb C}{\mathbb P}^3;\mathbb {Z})$ or $H^*(\widetilde {G}_2(\mathbb {R}^5);\mathbb {Z})$, then the representations at the fixed components are compatible with one of the standard actions; in the remaining two cases, the representation is strictly determined by the cohomology ring. Finally, our results suggest a natural question: Do the remaining two cohomology rings actually arise? This question is closely related to some interesting problems in symplectic topology, such as embeddings of ellipsoids.References
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Additional Information
- Susan Tolman
- Affiliation: Department of Mathematics, University of Illinois at Urbana-Champaign, Urbana, Illinois 61801
- Email: stolman@math.uiuc.edu
- Received by editor(s): September 19, 2007
- Published electronically: March 17, 2010
- Additional Notes: The author was partially supported by National Science foundation grant DMS #07-07122.
- © Copyright 2010 American Mathematical Society
- Journal: Trans. Amer. Math. Soc. 362 (2010), 3963-3996
- MSC (2000): Primary 53D20
- DOI: https://doi.org/10.1090/S0002-9947-10-04985-8
- MathSciNet review: 2638879