Algebraic obstructions and a complete solution of a rational retraction problem

For each compact smooth manifold $W$ containing at least two points we prove the existence of a compact nonsingular algebraic set $Z$ and a smooth map $g: Z \longrightarrow W$ such that, for every rational diffeomorphism $r:Z'\longrightarrow Z$ and for every diffeomorphism $s: W' \longrightarrow W$ where $Z'$ and $W'$ are compact nonsingular algebraic sets, we may fix a neighborhood $\mathcal{U}$ of $s^{-1} \circ g \circ r$ in $C^{\infty}(Z',W')$ which does not contain any regular rational map. Furthermore $s^{-1} \circ g \circ r$ is not homotopic to any regular rational map. Bearing in mind the case in which $W$ is a compact nonsingular algebraic set with totally algebraic homology, the previous result establishes a clear distinction between the property of a smooth map $f$ to represent an algebraic unoriented bordism class and the property of $f$ to be homotopic to a regular rational map. Furthermore we have: every compact Nash submanifold of $\mathbb{R}^n$ containing at least two points has not any tubular neighborhood with rational retraction.