Bi-Lipschitz-equivalent Aleksandrov surfaces, I
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A. Belen′kiĭ and Yu. Burago
Translated by: Yu. D. Burago - St. Petersburg Math. J. 16 (2005), 627-638
- DOI: https://doi.org/10.1090/S1061-0022-05-00869-1
- Published electronically: June 21, 2005
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Abstract:
In this first paper of two, it is proved that two compact Aleksandrov surfaces with bounded integral curvature and without peak points are bi-Lipschitz-equivalent if they are homeomorphic. Also, conditions under which two tubes with finite negative part of integral curvature are bi-Lipschitz-equivalent are considered. In the second paper an estimate depending only on several geometric characteristics is found for a bi-Lipschitz constant.References
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Bibliographic Information
- A. Belen′kiĭ
- Affiliation: St. Petersburg Branch, Steklov Mathematical Institute, Russian Academy of Sciences, Fontanka 27, St. Petersburg 191023, Russia
- Yu. Burago
- Affiliation: St. Petersburg Branch, Steklov Mathematical Institute, Russian Academy of Sciences, Fontanka 27, St. Petersburg 191023, Russia
- Email: yuburago@pdmi.ras.ru
- Received by editor(s): September 29, 2003
- Published electronically: June 21, 2005
- Additional Notes: The second author was partly supported by grants RFBR 02-01-00090, SS-1914.2003.1, and CRDF RM1-2381-ST-02
- © Copyright 2005 American Mathematical Society
- Journal: St. Petersburg Math. J. 16 (2005), 627-638
- MSC (2000): Primary 53C45
- DOI: https://doi.org/10.1090/S1061-0022-05-00869-1
- MathSciNet review: 2090849