On sets of integers which contain no three terms in geometric progression
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- by Nathan McNew;
- Math. Comp. 84 (2015), 2893-2910
- DOI: https://doi.org/10.1090/mcom/2979
- Published electronically: May 14, 2015
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Abstract:
The problem of looking for subsets of the natural numbers which contain no three-term arithmetic progressions has a rich history. Roth’s theorem famously shows that any such subset cannot have positive upper density. In contrast, Rankin in 1960 suggested looking at subsets without three-term geometric progressions, and constructed such a subset with density about 0.719. More recently, several authors have found upper bounds for the upper density of such sets. We significantly improve upon these bounds, and demonstrate a method of constructing sets with a greater upper density than Rankin’s set. This construction is optimal in the sense that our method gives a way of effectively computing the greatest possible upper density of a geometric-progression-free set. We also show that geometric progressions in $\mathbb {Z}/n\mathbb {Z}$ behave more like Roth’s theorem in that one cannot take any fixed positive proportion of the integers modulo a sufficiently large value of $n$ while avoiding geometric progressions.References
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Bibliographic Information
- Nathan McNew
- Affiliation: Department of Mathematics, Dartmouth College, Hanover, New Hampshire 03755
- Email: nathan.g.mcnew.gr@dartmouth.edu
- Received by editor(s): October 8, 2013
- Received by editor(s) in revised form: March 1, 2014
- Published electronically: May 14, 2015
- © Copyright 2015 American Mathematical Society
- Journal: Math. Comp. 84 (2015), 2893-2910
- MSC (2010): Primary 11B05, 11B75, 11Y60, 05D10
- DOI: https://doi.org/10.1090/mcom/2979
- MathSciNet review: 3378852