The univalence of an integral
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- by W. M. Causey
- Proc. Amer. Math. Soc. 27 (1971), 500-502
- DOI: https://doi.org/10.1090/S0002-9939-1971-0280700-9
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Abstract:
Let $f(z)$ be a normalized function, analytic and univalent in the open unit disc. It is shown that if $g(z) = \int _0^z {{{(f(t)/t)}^\alpha }dt}$, then $g$ is univalent in the open unit disc if $\alpha$ is a complex number satisfying $0 \leqq |\alpha | \leqq (\surd 2 - 1)/4$.References
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Bibliographic Information
- © Copyright 1971 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 27 (1971), 500-502
- MSC: Primary 30.42
- DOI: https://doi.org/10.1090/S0002-9939-1971-0280700-9
- MathSciNet review: 0280700