A continuum $X$ which has no confluent Whitney map for $2^{X}$
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- by WĹ‚odzimierz J. Charatonik
- Proc. Amer. Math. Soc. 92 (1984), 313-314
- DOI: https://doi.org/10.1090/S0002-9939-1984-0754729-7
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Abstract:
An example is shown of a continuum $X$ which has no confluent Whitney map for ${2^X}$. This answers two problems asked by Nadler [N].References
- Sam B. Nadler Jr., Hyperspaces of sets, Monographs and Textbooks in Pure and Applied Mathematics, Vol. 49, Marcel Dekker, Inc., New York-Basel, 1978. A text with research questions. MR 0500811
Bibliographic Information
- © Copyright 1984 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 92 (1984), 313-314
- MSC: Primary 54F20; Secondary 54B20, 54G20
- DOI: https://doi.org/10.1090/S0002-9939-1984-0754729-7
- MathSciNet review: 754729