On primes $p$ with $\sigma (p^ \alpha )=m^ 2$
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- by J. Chidambaraswamy and P. V. Krishnaiah PDF
- Proc. Amer. Math. Soc. 101 (1987), 625-628 Request permission
Abstract:
A. Takaku proved that for odd $\alpha \geqslant 3,\sigma ({p^\alpha }) = {m^2},p$ being a prime, implies that $p < {2^{{2^{\alpha + 1}}}}$. In this paper we extend this result to include almost all even integers $\alpha$.References
- A. Takaku, Prime numbers such that the sums of the divisors of their powers are perfect squares, Colloq. Math. 49 (1984), no. 1, 117–121. MR 774858, DOI 10.4064/cm-49-1-117-121
Additional Information
- © Copyright 1987 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 101 (1987), 625-628
- MSC: Primary 11A25; Secondary 11D41
- DOI: https://doi.org/10.1090/S0002-9939-1987-0911021-8
- MathSciNet review: 911021