Turing incomparability in Scott sets
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- by Antonín Kučera and Theodore A. Slaman
- Proc. Amer. Math. Soc. 135 (2007), 3723-3731
- DOI: https://doi.org/10.1090/S0002-9939-07-08871-5
- Published electronically: June 22, 2007
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Abstract:
For every Scott set $\mathcal F$ and every nonrecursive set $X$ in $\mathcal F$, there is a $Y \in \mathcal F$ such that $X$ and $Y$ are Turing incomparable.References
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Bibliographic Information
- Antonín Kučera
- Affiliation: Department of Theoretical Computer Science and Mathematical Logic, Faculty of Mathematics and Physics, Charles University, Malostranské nám. 25, 118 00 Praha 1, Czech Republic
- Email: kucera@ksi.mff.cuni.cz
- Theodore A. Slaman
- Affiliation: Department of Mathematics, The University of California, Berkeley, Berkeley, California 94720-3840
- MR Author ID: 163530
- Email: slaman@math.berkeley.edu
- Received by editor(s): February 20, 2006
- Received by editor(s) in revised form: August 14, 2006
- Published electronically: June 22, 2007
- Additional Notes: The first author was partially supported by the Research Project of the Ministry of Education of the Czech Republic MSM0021620838
The second author was partially supported by NSF grant DMS-0501167. - Communicated by: Julia Knight
- © Copyright 2007
American Mathematical Society
The copyright for this article reverts to public domain 28 years after publication. - Journal: Proc. Amer. Math. Soc. 135 (2007), 3723-3731
- MSC (2000): Primary 03D28
- DOI: https://doi.org/10.1090/S0002-9939-07-08871-5
- MathSciNet review: 2336589