Explicit free groups in division rings
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- by J. Z. Gonçalves and D. S. Passman
- Proc. Amer. Math. Soc. 143 (2015), 459-468
- DOI: https://doi.org/10.1090/S0002-9939-2014-12230-1
- Published electronically: October 1, 2014
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Abstract:
Let $D$ be a division ring of characteristic $\neq 2$ and suppose that the multiplicative group $D^\bullet =D\setminus \{0\}$ has a subgroup $G$ isomorphic to the Heisenberg group. Then we use the generators of $G$ to construct an explicit noncyclic free subgroup of $D^\bullet$. The main difficulty occurs here when $D$ has characteristic $0$ and the commutators in $G$ are algebraic over $\mathbb {Q}$.References
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Bibliographic Information
- J. Z. Gonçalves
- Affiliation: Department of Mathematics, University of São Paulo, São Paulo, 05508-090, Brazil
- MR Author ID: 75040
- Email: jz.goncalves@usp.br
- D. S. Passman
- Affiliation: Department of Mathematics, University of Wisconsin, Madison, Wisconsin 53706
- MR Author ID: 136635
- Email: passman@math.wisc.edu
- Received by editor(s): February 27, 2013
- Published electronically: October 1, 2014
- Additional Notes: The first author’s research was supported in part by Grant CNPq 300.128/2008-8 and by Fapesp-Brazil, Proj. Tematico 2009/52665-0
- Communicated by: Lev Borisov
- © Copyright 2014
American Mathematical Society
The copyright for this article reverts to public domain 28 years after publication. - Journal: Proc. Amer. Math. Soc. 143 (2015), 459-468
- MSC (2010): Primary 16K40; Secondary 20C07
- DOI: https://doi.org/10.1090/S0002-9939-2014-12230-1
- MathSciNet review: 3283636