A note on the Sobolev trace inequality
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- by Pak Tung Ho
- Proc. Amer. Math. Soc. 150 (2022), 1257-1267
- DOI: https://doi.org/10.1090/proc/15751
- Published electronically: January 5, 2022
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Abstract:
Consider the classical Sobolev trace inequality \begin{equation*} \|\nabla \varphi \|_{L^2(\mathbb {R}^n_+)} \geq K\|\varphi \|_{L^{\frac {2(n-1)}{n-2}}(\partial \mathbb {R}^n_+)} \end{equation*} for all $\varphi \in W^{1,2}_0(\mathbb {R}^n_+)$, where $K$ is the best constant. Here, $W^{1,2}_0(\mathbb {R}^n_+)$ is the space obtained by taking the completion in the norm $\|\nabla \varphi \|_{L^2(\mathbb {R}^n_+)}$ of the set of all smooth functions with support contained in the closure of $\mathbb {R}^n_+$, and $n\geq 3$. Let $\mathcal {M}$ be the set of functions for which we have equality in the Sobolev trace inequality above. In this note, we show that there is a positive constant $\alpha$ such that \begin{equation*} \|\nabla \varphi \|_{L^2(\mathbb {R}^n_+)}^2-K^2 \|\varphi \|_{L^{\frac {2(n-1)}{n-2}}(\partial \mathbb {R}^n_+)}^2\geq \alpha d(\varphi ,\mathcal {M})^2 \end{equation*} for all $\varphi \in W^{1,2}_0(\mathbb {R}^n_+)$, where $d$ is the distance in the Sobolev space $W^{1,2}_0(\mathbb {R}^n_+)$.References
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Bibliographic Information
- Pak Tung Ho
- Affiliation: Department of Mathematics, Sogang University, Seoul 04107, Korea
- MR Author ID: 773104
- Email: paktungho@yahoo.com.hk
- Received by editor(s): November 22, 2020
- Received by editor(s) in revised form: June 23, 2021, and July 2, 2021
- Published electronically: January 5, 2022
- Communicated by: Ariel Barton
- © Copyright 2022 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 150 (2022), 1257-1267
- MSC (2020): Primary 46E35; Secondary 35A23
- DOI: https://doi.org/10.1090/proc/15751
- MathSciNet review: 4375719