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Transactions of the American Mathematical Society

Published by the American Mathematical Society since 1900, Transactions of the American Mathematical Society is devoted to longer research articles in all areas of pure and applied mathematics.

ISSN 1088-6850 (online) ISSN 0002-9947 (print)

The 2020 MCQ for Transactions of the American Mathematical Society is 1.48.

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Basic sequences and subspaces in Lorentz sequence spaces without local convexity
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by Nicolae Popa PDF
Trans. Amer. Math. Soc. 263 (1981), 431-456 Request permission

Abstract:

After some preliminary results $(\S 1)$, we give in $\S 2$ another proof of the result of N. J. Kalton [5] concerning the unicity of the unconditional bases of ${l_p}$, $0 < p < 1$. Using this result we prove in §3 the unicity of certain bounded symmetric block bases of the subspaces of the Lorentz sequence spaces $d(w,p)$, $0 < p < 1$. In $\S 4$ we show that every infinite dimensional subspace of $d(w,p)$ contains a subspace linearly homeomorphic to ${l_p}$, $0 < p < 1$. Unlike the case $p \geqslant 1$ there are subspaces of $d(w,p)$, $0 < p < 1$, which contain no complemented subspaces of $d(w,p)$ linearly homeomorphic to ${l_p}$. In fact there are spaces $d(w,p)$, $0 < p < 1$, which contain no complemented subspaces linearly homeomorphic to ${l_p}$. We conjecture that this is true for every $d(w,p)$, $0 < p < 1$. The answer to the previous question seems to be important: for example we can prove that a positive complemented sublattice $E$ of $d(w,p)$, $0 < p < 1$, with a symmetric basis is linearly homeomorphic either to ${l_p}$ or to $d(w,p)$; consequently, a positive answer to this question implies that $E$ is linearly homeomorphic to $d(w,p)$. In $\S 5$ we are able to characterise the sublattices of $d(w,p)$, $p = {k^{ - 1}}$ (however under a supplementary restriction concerning the sequence $({w_n})_{n = 1}^\infty )$, which are positive and contractive complemented, as being the order ideals of $d(w,p)$. Finally, in $\S 6$, we characterise the Mackey completion of $d(w,p)$ also in the case $p = {k^{ - 1}}$, $k \in {\mathbf {N}}$.
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Additional Information
  • © Copyright 1981 American Mathematical Society
  • Journal: Trans. Amer. Math. Soc. 263 (1981), 431-456
  • MSC: Primary 46A45; Secondary 46A10
  • DOI: https://doi.org/10.1090/S0002-9947-1981-0594418-7
  • MathSciNet review: 594418