Metric rigidity in $E^{n}$
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- by Brian M. Scott and Ralph Jones PDF
- Proc. Amer. Math. Soc. 53 (1975), 219-222 Request permission
Abstract:
In answer to a question rasied by L. Janos, it is shown (i) that ${E^n}$ is not a finite union of metrically rigid subsets; (ii) that if ${2^\omega } > {\kappa ^ + }$, then ${E^n}$ is not the union of $\kappa$ metrically rigid subsets, where $\kappa$ is an infinite cardinal; and (iii) that if ${2^\omega } = {\kappa ^ + }$, then ${E^1}$ is the union of $\kappa$ metrically rigid subsets, and hence that ${E^1}$ is a countable union of metrically rigid subsets iff the continuum hypothesis holds. ($A \subseteq {E^n}$ is metrically rigid iff no two distinct two-point subsets of $A$ are isometric.) Open question: assuming the continuum hypothesis, can ${E^n}$ be written as a countable union of metrically rigid subsets if $n > 1$?References
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L. Janos, On rigidity of metrics, Notices Amer. Math. Soc. 18 (1971), 436. Abstract #71T-G40.
—, On rigidity of subsets in metric spaces. Preliminary report, Notices Amer. Math. Soc. 20 (1973), A343-A344. Abstract #73T-G58.
R. Jones, Rigid sets of cardinal $c$ in ${E^n}$ (submitted).
Additional Information
- © Copyright 1975 American Mathematical Society
- Journal: Proc. Amer. Math. Soc. 53 (1975), 219-222
- MSC: Primary 54E40
- DOI: https://doi.org/10.1090/S0002-9939-1975-0377824-8
- MathSciNet review: 0377824