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Proceedings of the American Mathematical Society

Published by the American Mathematical Society since 1950, Proceedings of the American Mathematical Society is devoted to shorter research articles in all areas of pure and applied mathematics.

ISSN 1088-6826 (online) ISSN 0002-9939 (print)

The 2020 MCQ for Proceedings of the American Mathematical Society is 0.85.

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Operators associated with a pair of nonnegative matrices
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by Gerald E. Suchan PDF
Proc. Amer. Math. Soc. 35 (1972), 53-54 Request permission

Abstract:

Let ${A_{m \times n}},{B_{m \times n}},{X_{n \times 1}}$, and ${Y_{m \times 1}}$ be matrices whose entries are nonnegative real numbers and suppose that no row of A and no column of B consists entirely of zeroes. Define the operators U, T and T’ by ${(UX)_i} = X_i^{ - 1}[{\text {or}}{(UY)_i} = Y_i^{ - 1}]$, $T = U{B^t}UA$ and $T’ = UAU{B^t}$. T is called irreducible if for no nonempty proper subset S of $\{ 1, \cdots ,n\}$ it is true that ${X_i} = 0,i \in S;{X_i} \ne 0,i \notin S$, implies ${(TX)_i} = 0,i \in S;{(TX)_i} \ne 0,i \notin S$. M. V. Menon proved the following Theorem. If T is irreducible, there exist row-stochastic matrices ${A_1}$ and ${A_2}$, a positive number $\theta$, and two diagonal matrices D and E with positive main diagonal entries such that $DAE = {A_1}$ and $\theta DBE = A_2^t$. Since an analogous theorem holds for T’, it is natural to ask if it is possible that T’ be irreducible if T is not. It is the intent of this paper to show that T’ is irreducible if and only if T is irreducible.
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Additional Information
  • © Copyright 1972 American Mathematical Society
  • Journal: Proc. Amer. Math. Soc. 35 (1972), 53-54
  • MSC: Primary 15A48
  • DOI: https://doi.org/10.1090/S0002-9939-1972-0296092-6
  • MathSciNet review: 0296092